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Question

Chemistry Question on Acids and Bases

The pH value of an acid is 55 and its concentration is 1 M. What is the value of KaK_{a} for the acid?

A

10710^{-7}

B

10510^{-5}

C

101010^{-10}

D

10810^{-8}

Answer

101010^{-10}

Explanation

Solution

By using pH=logKaCpH =-\log \sqrt{K_{a} \cdot C} 5=logKa×1=12logKa5=-\log \sqrt{K_{a} \times 1} =-\frac{1}{2} \log K_{a} logKa=10\log K_{a} =-10 Ka=1010K_{a} =10^{-10} Hence, dissociation constant (Ka)=1010(K_a) = 10^{-10}