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Question

Chemistry Question on Acids and Bases

The pHpH of aqueous solution of ammonium formate is (pKa\left( p K_{a}\right. of HCOOH=3.8HCOOH =3.8 and pKbpK _{b} of NH3=4.8)\left.NH _{3}=4.8\right)

A

7

B

6

C

6.5

D

8.9

Answer

6.5

Explanation

Solution

For a salt of weak acid and weak base, its pH=7+12pKa12pKbpH = 7+\frac{1}{2}pK_{a^{-}} \frac{1}{2}pK_{b} =7+12×3.812×4.8=6.5= 7+\frac{1}{2}\times3.8-\frac{1}{2}\times4.8 = 6.5