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Question: The \(pH\) of a solution in which the \(\lbrack H^{+}\rbrack = 0.01,\) is....

The pHpH of a solution in which the [H+]=0.01,\lbrack H^{+}\rbrack = 0.01, is.

A

2

B

1

C

4

D

3

Answer

2

Explanation

Solution

pH=−log⁡[H+]pH = - \log{}\lbrack H^{+}\rbrack;[H+]=0.01N\lbrack H^{+}\rbrack = 0.01N

pH=−log⁡[10−2]pH = - \log{}\lbrack 10^{- 2}\rbrack;pH=2pH = 2