Question
Chemistry Question on Acids and Bases
The pH of 10−8MNaOH is:
A
8
B
6
C
6.96
D
7.04
Answer
7.04
Explanation
Solution
For 10−8MNaOH,
[OH−]=10−8+10−7 (from water)
=11×10−8
∴pOH=−log[OH−]=−log11×10−8
=8−1.04=6.96
pH=14−6.96=7.04
The pH of 10−8MNaOH is:
8
6
6.96
7.04
7.04
For 10−8MNaOH,
[OH−]=10−8+10−7 (from water)
=11×10−8
∴pOH=−log[OH−]=−log11×10−8
=8−1.04=6.96
pH=14−6.96=7.04