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Question

Chemistry Question on Equilibrium

The pH of 103^{-3} M solution of NaOH is

A

3

B

11

C

4

D

12

Answer

11

Explanation

Solution

[OH]=103M[OH^-]=10^{-3}M
pOH=-log[OH]=log(103)=3[OH^-]=-log(10^{-3})=3
pH=11