Question
Question: The pH of 0.1M monobasic acid with dissociation constant \({10^{ - 3}}\) will be:...
The pH of 0.1M monobasic acid with dissociation constant 10−3 will be:
Solution
A monobasic acid is also known as monoprotic acid which is able to donate one proton per molecule, and has only one hydrogen atom. First find the value of pKa using the dissociation constant. pH of an acid is the sum of pKa and the logarithm of ratio of concentrations of salt and acid. The concentration of acid is already given and the concentration of the mono-basic salt is 1. Substitute these values and find the pH
Step by step answer: We are given that molarity of a monobasic acid is 0.1M and its dissociation constant is 10−3
pKa is used to indicate the strength of an acid and the value of pKa is the negative logarithm of the acid dissociation constant.
pKa=−log10Ka Ka=10−3 →pKa=−log10(10−3) (∵logam=mloga;logaa=1) →pKa=−(−3)log1010 →pKa=3×1 ∴pKa=3
Therefore the value of pKa is 3.
The pH, which is also known as the potential of hydrogen, is a scale used to specify acidity or basicity of an aqueous solution.
pH is defined as the sum of pKa and the logarithm of ratio of concentration of the salt and concentration of the acid.
pH=pKa+log[Acid][Salt]
The value of pKa is 3, the concentration of salt is 1M and concentration of acid given is 0.1M.
Substituting the values in the above formula, we get
pH=pKa+log[Acid][Salt] pKa=3,[Salt]=1M,[Acid]=0.1M →pH=3+log100.11 →pH=3+log1010 →pH=3+1 ∴pH=4
The pH of the given monobasic acid with 0.1M is 4.
Note: If the value of pH is lower than pKa then the acid will be protonated (addition of hydrogen ions) and if the value of pH is greater than pKa then the acid will be deprotonated (losing of hydrogen ions).
Acidic solutions generally have lower pH values than basic solutions. pH below 7 is considered to be an acid and above is considered to be a base. And if the pH is 7 then the solution is neutral. Water is a neutral solution.