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Question: The pH of 0.1M monobasic acid with dissociation constant \({10^{ - 3}}\) will be:...

The pH of 0.1M monobasic acid with dissociation constant 103{10^{ - 3}} will be:

Explanation

Solution

A monobasic acid is also known as monoprotic acid which is able to donate one proton per molecule, and has only one hydrogen atom. First find the value of pKap{K_a} using the dissociation constant. pH of an acid is the sum of pKap{K_a} and the logarithm of ratio of concentrations of salt and acid. The concentration of acid is already given and the concentration of the mono-basic salt is 1. Substitute these values and find the pH

Step by step answer: We are given that molarity of a monobasic acid is 0.1M and its dissociation constant is 103{10^{ - 3}}
pKap{K_a} is used to indicate the strength of an acid and the value of pKap{K_a} is the negative logarithm of the acid dissociation constant.
pKa=log10Ka Ka=103 pKa=log10(103) (logam=mloga;logaa=1) pKa=(3)log1010 pKa=3×1 pKa=3  p{K_a} = - {\log _{10}}{K_a} \\\ {K_a} = {10^{ - 3}} \\\ \to p{K_a} = - {\log _{10}}\left( {{{10}^{ - 3}}} \right) \\\ \left( {\because \log {a^m} = m\log a;{{\log }_a}a = 1} \right) \\\ \to p{K_a} = - \left( { - 3} \right){\log _{10}}10 \\\ \to p{K_a} = 3 \times 1 \\\ \therefore p{K_a} = 3 \\\
Therefore the value of pKap{K_a} is 3.
The pH, which is also known as the potential of hydrogen, is a scale used to specify acidity or basicity of an aqueous solution.
pH is defined as the sum of pKap{K_a} and the logarithm of ratio of concentration of the salt and concentration of the acid.
pH=pKa+log[Salt][Acid]pH = p{K_a} + \log \dfrac{{\left[ {Salt} \right]}}{{\left[ {Acid} \right]}}
The value of pKap{K_a} is 3, the concentration of salt is 1M and concentration of acid given is 0.1M.
Substituting the values in the above formula, we get
pH=pKa+log[Salt][Acid] pKa=3,[Salt]=1M,[Acid]=0.1M pH=3+log1010.1 pH=3+log1010 pH=3+1 pH=4  pH = p{K_a} + \log \dfrac{{\left[ {Salt} \right]}}{{\left[ {Acid} \right]}} \\\ p{K_a} = 3,\left[ {Salt} \right] = 1M,\left[ {Acid} \right] = 0.1M \\\ \to pH = 3 + {\log _{10}}\dfrac{1}{{0.1}} \\\ \to pH = 3 + {\log _{10}}10 \\\ \to pH = 3 + 1 \\\ \therefore pH = 4 \\\
The pH of the given monobasic acid with 0.1M is 4.

Note: If the value of pH is lower than pKap{K_a} then the acid will be protonated (addition of hydrogen ions) and if the value of pH is greater than pKap{K_a} then the acid will be deprotonated (losing of hydrogen ions).
Acidic solutions generally have lower pH values than basic solutions. pH below 7 is considered to be an acid and above is considered to be a base. And if the pH is 7 then the solution is neutral. Water is a neutral solution.