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Question

Chemistry Question on Acids and Bases

The pH of 0.01 M KOH is

A

2

B

8

C

14

D

12

Answer

12

Explanation

Solution

pOH=−log[OH−]=−log(0.01)=2 {pOH = - log[OH^{-}] = - log(0.01) = 2}
pH+pOH=14{pH + pOH = 14}
pH=14−pOH=14−2=12{pH = 14 - pOH = 14 - 2 = 12}