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Question: The perpendicular PL, PM are drawn from any point P on the rectangular hyperbola xy=25 to the asympt...

The perpendicular PL, PM are drawn from any point P on the rectangular hyperbola xy=25 to the asymptotes the locus of the mid point of OP is curve with eccentricity

A

An ellipse with e = 2\sqrt{2}

B

An hyperbola with e =2\sqrt{2}

C

A parabola e = 1/2\sqrt{2}

D

None of these

Answer

An hyperbola with e =2\sqrt{2}

Explanation

Solution

Let R be the mid point of OP

As xy = 52 = c2

∴ P(x, y) = (5t,5t)\left( 5t,\frac{5}{t} \right) and OMPL is a rectangle

Coordinate of R = (5t2,6mu52t)\left( \frac{5t}{2},\mspace{6mu}\frac{5}{2t} \right)

Now locus of Q is xy = 5t2x52t=254\frac{5t}{2}x\frac{5}{2t} = \frac{25}{4}

Which is a rectangular hyperbola, whose eccentricity is given e2 = a2+b2a26mu=6mua2+b2b26mu(=a=b)\frac{a^{2} + b^{2}}{a^{2}}\mspace{6mu} = \mspace{6mu}\frac{a^{2} + b^{2}}{b^{2}}\mspace{6mu}(\because = a = b)

∴ e2 = 2a2a2=2\frac{2a^{2}}{a^{2}} = 2

⇒ e2 = 2 ∴ e = 2\sqrt{2}