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Question

Mathematics Question on Coplanarity of Two Lines

The perpendicular distance (d) of a line Ax + By + C = 0 from a point (x1,y1)(x_1, y_1) is given by :

A

d=Ax1+By1+CA2+B2d= \frac{\left|Ax_{1} + By_{1} +C\right|}{\sqrt{A^{2}+B^{2}}}

B

d=Ax1By1+CA2+B2d= \frac{\left|Ax_{1} - By_{1} +C\right|}{\sqrt{A^{2}+B^{2}}}

C

d=A2+B2Ax1+By1+Cd= \frac{\sqrt{A^{2}+B^{2}}}{\left|Ax_{1} + By_{1} +C\right|}

D

d=A2B2Ax1+By1+Cd= \frac{\sqrt{A^{2}- B^{2}}}{\left|Ax_{1} + By_{1} +C\right|}

Answer

d=Ax1+By1+CA2+B2d= \frac{\left|Ax_{1} + By_{1} +C\right|}{\sqrt{A^{2}+B^{2}}}

Explanation

Solution

d=Ax1+By1+CA2+B2d= \frac{\left|Ax_{1} + By_{1} +C\right|}{\sqrt{A^{2}+B^{2}}}