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Question: The periodic time of a body executing simple harmonic motion is 3 sec. After how much interval from ...

The periodic time of a body executing simple harmonic motion is 3 sec. After how much interval from time t = 0, its displacement will be half of its amplitude

A

18\frac{1}{8}sec

B

16\frac{1}{6}sec

C

14\frac{\mathbf{1}}{\mathbf{4}}sec

D

13\frac{1}{3}sec

Answer

14\frac{\mathbf{1}}{\mathbf{4}}sec

Explanation

Solution

y=asin2πTty = a\sin\frac{2\pi}{T}ta2=asin2πt3\frac{a}{2} = a\sin\frac{2\pi t}{3}12=sin2πt3\frac{1}{2} = \sin\frac{2\pi t}{3}

⇒ sin2πt3=sinπ6\frac{2\pi t}{3} = \sin\frac{\pi}{6}2πt3=π6\frac{2\pi t}{3} = \frac{\pi}{6}t=14sect = \frac{1}{4}\sec