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Question: The period of the function \[tan\left( 3x+5 \right)\]is A. \[\dfrac{2\pi }{3}\] B. \[\dfrac{\pi...

The period of the function tan(3x+5)tan\left( 3x+5 \right)is
A. 2π3\dfrac{2\pi }{3}
B. π6\dfrac{\pi }{6}
C. π3\dfrac{\pi }{3}
D. None of these

Explanation

Solution

Hint: Use the concept that the period of the function of the form a×tan(bx  +  c)  +  disperiodicity  of  tan(x)ba\times \tan \left( bx\;+\;c \right)\;+\;d\,\,is\,\,\dfrac{\text{periodicity}\;\text{of}\;\tan \left( x \right)}{|b|}. Also, use the concept that the period of tan(x)  isπ\tan \left( x \right)\,\,\;\text{is}\,\,\pi . Now, we just need to just compare the function given with the standard form as shown in the formula and then use the above formula to get the required period.

Complete step-by-step answer:
In the question, we have to find the period of the function tan(3x+5)tan\left( 3x+5 \right). Now, it is known that if the function is of the form a×tan(bx  +  c)  +  da\times \tan \left( bx\;+\;c \right)\;+\;d, then the period of that will be given by periodicity  of  tan(x)b\dfrac{\text{periodicity}\;\text{of}\;\tan \left( x \right)}{|b|}. So here, we can compare the given function tan(3x+5)tan\left( 3x+5 \right)with the expression a×tan(bx  +  c)  +  da\times \tan \left( bx\;+\;c \right)\;+\;d and we see that a=1, d=0, b=3 and c=5a=1,\text{ }d=0,\text{ }b=3\text{ }and\text{ }c=5. So, the period will be then found directly by using the above formula.
So here, we will see that the period of the function tan x is π\pi , as this is the interval cafter which the function tan x is repeating itself. Now, this means that after every π\pi interval, we will have exactly the same behaviour of the function tan x.
Now, applying the formula that period of a×tan(bx  +  c)  +  d=periodicity  of  tan(x)ba\times \tan \left( bx\;+\;c \right)\;+\;d=\dfrac{\text{periodicity}\;\text{of}\;\tan \left( x \right)}{|b|}, so the period of tan(3x+5)isperiodicity  of  tan(x)3tan\left( 3x+5 \right)\,\,\,is\,\,\dfrac{\text{periodicity}\;\text{of}\;\tan \left( x \right)}{3}as we just have seen that b=3.
Also, we have seen that the period of tan x is π\pi . So, finally, the required period is s follows:

& tan\left( 3x+5 \right)\,\,\,is\,\, \\\ & \dfrac{\text{periodicity}\;\text{of}\;\tan \left( x \right)}{3}=\dfrac{\pi }{3} \\\ \end{aligned}$$ So, the correct answer is option C which is $$\dfrac{\pi }{3}$$. Note: When we are finding the period of tan x, then it will not be $$2\pi $$, as we have the period of sin x and cos x. But here the period of tan x is just $$\pi $$, which is important to take care about.