Question
Question: The period of the function \[tan\left( 3x+5 \right)\]is A. \[\dfrac{2\pi }{3}\] B. \[\dfrac{\pi...
The period of the function tan(3x+5)is
A. 32π
B. 6π
C. 3π
D. None of these
Solution
Hint: Use the concept that the period of the function of the form a×tan(bx+c)+dis∣b∣periodicityoftan(x). Also, use the concept that the period of tan(x)isπ. Now, we just need to just compare the function given with the standard form as shown in the formula and then use the above formula to get the required period.
Complete step-by-step answer:
In the question, we have to find the period of the function tan(3x+5). Now, it is known that if the function is of the form a×tan(bx+c)+d, then the period of that will be given by ∣b∣periodicityoftan(x). So here, we can compare the given function tan(3x+5)with the expression a×tan(bx+c)+d and we see that a=1, d=0, b=3 and c=5. So, the period will be then found directly by using the above formula.
So here, we will see that the period of the function tan x is π, as this is the interval cafter which the function tan x is repeating itself. Now, this means that after every π interval, we will have exactly the same behaviour of the function tan x.
Now, applying the formula that period of a×tan(bx+c)+d=∣b∣periodicityoftan(x), so the period of tan(3x+5)is3periodicityoftan(x)as we just have seen that b=3.
Also, we have seen that the period of tan x is π. So, finally, the required period is s follows: