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Question: : The period of \[sinkx\] is A. \( \dfrac{\pi }{k} \) B. \( \dfrac{{2\pi }}{k} \) C. \( \dfr...

: The period of sinkxsinkx is
A. πk\dfrac{\pi }{k}
B. 2πk\dfrac{{2\pi }}{k}
C. 2πk\dfrac{{2\pi }}{{\left| k \right|}}
D. πk\dfrac{\pi }{{\left| k \right|}}

Explanation

Solution

Hint : To answer the period of sinkxsinkx first of all we should know the period of sinxsinx. Once we noted the period of sinxsinx just divide that period by the coefficient multiplied with x in sinxsinx. That will be the period of given sin function.

Complete step-by-step answer :
Given function is sinkxsinkx.
We have to calculate the period of sinkxsinkx.
We know that the period of sinaxsinax is 2πa\dfrac{{2\pi }}{{\left| a \right|}} means the coefficient multiplied with x should be in division.
So now to calculate the period of sinkxsinkx we have to know the period of sinxsinxfirst.
The period of sinxsinx is 2π2\pi as we all know.
Here x is multiplied by k. so to find the period of sinkxsinkx we have to divide the period of sinxsinx by k\left| k \right| i.e. 2π2\pi should be divided by k\left| k \right| .
Hence the period of sinkxsinkx is 2πk\dfrac{{2\pi }}{{\left| k \right|}} .

So, the correct answer is “Option C”.

Note : Here in this solution we have noticed that the period of sinxsinx is divided by k\left| k \right| instead of k. Because the period of any function cannot be negative it can be fraction but cant be negative.