Question
Question: : The period of \[sinkx\] is A. \( \dfrac{\pi }{k} \) B. \( \dfrac{{2\pi }}{k} \) C. \( \dfr...
: The period of sinkx is
A. kπ
B. k2π
C. ∣k∣2π
D. ∣k∣π
Solution
Hint : To answer the period of sinkx first of all we should know the period of sinx. Once we noted the period of sinx just divide that period by the coefficient multiplied with x in sinx. That will be the period of given sin function.
Complete step-by-step answer :
Given function is sinkx.
We have to calculate the period of sinkx.
We know that the period of sinax is ∣a∣2π means the coefficient multiplied with x should be in division.
So now to calculate the period of sinkx we have to know the period of sinxfirst.
The period of sinx is 2π as we all know.
Here x is multiplied by k. so to find the period of sinkx we have to divide the period of sinx by ∣k∣ i.e. 2π should be divided by ∣k∣ .
Hence the period of sinkx is ∣k∣2π .
So, the correct answer is “Option C”.
Note : Here in this solution we have noticed that the period of sinx is divided by ∣k∣ instead of k. Because the period of any function cannot be negative it can be fraction but cant be negative.