Question
Question: The period of \({{\sin }^{4}}x+{{\cos }^{4}}x\) is. A. \(\dfrac{\pi }{2}\) B. \(\pi \) C. \(2\...
The period of sin4x+cos4x is.
A. 2π
B. π
C. 2π
D. None of these
Solution
Hint: We will be using the concept of function to solve the problem. We will be using the periodicity of sine and cosine function and will also be utilizing the general condition for any function to be periodic.
Complete step-by-step solution -
We have been given a function f(x)=sin4x+cos4x.
Now, we have to find the period of f(x).
We know that periodic functions are those who repeat their value after a fixed constant interval called period.
In generally a function f(x) such that,
f(T+x)=f(x)
Then T is the period of the function. For example, if
f(x)=sinx
We know that sin(2π+x)=sinx
Also, if f(x)=sinx
Then,
f(π+x)=sin(π+x)2=(−sin(x))2=sin2x⇒f(π+x)=f(x)
And therefore the period of sin2x is π.
Similarly, the period of cos2x is also π.
Now, we have to find the period of f(x)=sin4x+cos4x.
f(x)=sin4x+cos4xf(T+x)=sin4(T+x)+cos4(T+x)
Now, if we put T=2π, we see that,
f(2π+x)=sin4(2π+x)+cos4(2π+x)
Also, we know that,
sin(2π+x)=sin(x)cos(2π+x)=−cos(x)
⇒f(2π+x)=cos4x+sin4x
Now, since,
f(x)=f(2π+x)
Therefore, the period is 2π.
Note: To solve these types of functions it is advised to remember the period of function like sin x, cos x which is 2π. Also, it is noted that the for sin4x+cos4xf(π+x)=f(x). Also, but π is still not period because period is always the least value of T which satisfies f(T+x)=f(x)