Question

The period of simple pendulum is measured as T in a stationary lift. If the lift moves upwards with an acceleration of 5 g, the period will be

• A. The same
• B. Increased by 3/5
• C. Decreased by 2/3 times
• D. None of the above

Answer 1

Answer: (D)

None of the above

Answer 2

$\frac{T^{'}}{T} = \sqrt{\frac{g}{g' + a}} = \sqrt{\frac{g}{g + 5g}} = \sqrt{\frac{1}{6}}$⇒ $T^{'} = \frac{T}{\sqrt{6}}$