Question

The period of SHM of a particle is 12 s. The phase difference between the positions at $t=3\,s$ and $t=4s$ will be:

• A. $\pi /4$
• B. $3\pi /5$
• C. $\pi /6$
• D. $\pi /=2$

Answer 1

Answer: (C)

$\pi /6$

Answer 2

The phase of particle at $t=3\,s$ is $\text{o }\\!\\!|\\!\\!\text{ =}\omega \text{t=}\left( \frac{2\pi }{T} \right)t$ $=\frac{2\pi \times 3}{12}=\frac{\pi }{2}$ At $t=4s$ $\text{o }\\!\\!|\\!\\!\text{ =}\omega t=\left( \frac{2\pi }{T} \right)t$ $=\frac{2\pi \times 4}{12}=\frac{2\pi }{3}$ Phase difference $\Delta \text{o }\\!\\!|\\!\\!\text{ =}\,\text{o}{{\text{ }\\!\\!|\\!\\!\text{ }}_{2}}-\text{o}{{\text{ }\\!\\!|\\!\\!\text{ }}_{1}}=\frac{2\pi }{3}-\frac{\pi }{2}=\frac{\pi }{6}$