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Question: The period of revolution of planet A around the sun is 8 times that of B. The distance of A from the...

The period of revolution of planet A around the sun is 8 times that of B. The distance of A from the sun is how many times greater than that of B from the sun

A

2

B

3

C

4

D

5

Answer

4

Explanation

Solution

TATB=(rArB)3/2\frac { T _ { A } } { T _ { B } } = \left( \frac { r _ { A } } { r _ { B } } \right) ^ { 3 / 2 } 8=(rArB)3/2\Rightarrow 8 = \left( \frac { r _ { A } } { r _ { B } } \right) ^ { 3 / 2 } rA=(8)2/3rB\Rightarrow r _ { A } = ( 8 ) ^ { 2 / 3 } r _ { B }