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Question: The period of revolution of a charged particle inside a cyclotron does not depend on: A. The magne...

The period of revolution of a charged particle inside a cyclotron does not depend on:
A. The magnetic induction
B. The charge of the particle
C. The velocity of the particle
D. The mass of the particle

Explanation

Solution

Cyclotron hastens up charged particles to very large scales energies. Its working principle is: When a charged particle such as electron and proton moves normally to a magnetic field, it experiences magnetic force and moves in a circular path.

Complete step by step solution:
Cyclotron: A cyclotron is an accelerator of particles. It is a powered electrical machine producing a beam of charged parts which is used for medical purpose, industrial and investigational applications. Cyclotron was invented by Ernest O. Lawrence in 192919301929 - 1930 at the University of California. In an outward path from the center of a flat, cylindrical vacuum chamber, a cyclotron accelerates charged particles. The particles are tracked by a static magnetic field on a spiral trajectory and accelerated through a quickly varying electric field (radio frequency). For this invention, Lawrence received the 19391939 Nobel Prize for Physics.

Velocity: The velocity of an object is the rate of change of position relative to a reference framework and depends on time. Velocity is equivalent to the specified speed and direction of motion of an object (e.g. northward 60km/h60\,{\text{km/h}}). Velocity, the branch of classical mechanics which describes the motion of bodies, is a fundamental concept in kinematics.

The particle moves in a plane perpendicular to B when the velocity of a charged particle is perpendicular to a uniform B magnetic field. This motion is referred to as a cyclotron. Here is the necessary magnetic force to keep the particle in a circle motion.

Here,

FB=qvB =mv2r  {F_B} = qvB \\\ = \dfrac{{m{v^2}}}{r} \\\

Or,
r=mv/qBr = mv/qB
So, the period of revolution,
T=2πrv=2πmqBT = \dfrac{{2\pi r}}{v} = \dfrac{{2\pi m}}{{qB}}
The revolution period does not therefore depend on velocity, vv.

Hence, the required answer is C.

Note: When the velocity of a charged particle is perpendicular to a uniform B magnetic field, the particle moves in a plane perpendicular to B. This motion is termed a cyclotron. Here's the magnetic force needed to keep the particle in motion in a circle.