Question

The period of oscillation of a simple pendulum of constant length at earth surface is T. Its period inside a mine is

• A. Greater than T
• B. Less than T
• C. Equal to T
• D. Cannot be compared

Answer 1

Answer: (A)

Greater than T

Answer 2

Inside the mine g decreases

hence from $T = 2\pi\sqrt{\frac{l}{g}}$; T increase