Question
Question: The period of oscillation of a simple pendulum in the experiment is recorded as \( 2.63s, \) \( 2.56...
The period of oscillation of a simple pendulum in the experiment is recorded as 2.63s, 2.56s, 2.42s, 2.71s, and 2.80s respectively. The average absolute error is:
(A) 0.1s
(B) 0.11s
(C) 0.01s
(D) 1.0s
Solution
To solve this question, we need to find out the mean of the values given in the problem. From the mean, we can find out the individual absolute errors. Then we can determine the mean of the absolute errors.
Formula used: The formula used in solving this question is
μ=nx1+x2+x3+..........+xn , where μ is the average of the n values x1 , x2 , ………, xn .
Complete step by step solution:
To find the absolute errors of each of the measurements, we need to find out the mean of all the measurements given in the problem.
The mean μ of the measurements is given by
μ=5T1+T2+T3+T4+T5
μ=52.63+2.56+2.42+2.71+2.80
On solving we get
μ=2.624
We need to round off this value to the same number of decimal places as the values are given in the problem
∴μ=2.62
Now, to find the absolute errors, we need to subtract the mean from each of the values given.
For the first measurement
ΔT1=∣2.63−2.62∣=0.01s
For the second measurement
ΔT2=∣2.56−2.62∣=0.06s
For the third measurement
ΔT3=∣2.42−2.62∣=0.20s
For the fourth measurement
ΔT4=∣2.71−2.62∣=0.09s
For the fifth measurement
ΔT5=∣2.80−2.62∣=0.18s
Now, the mean of the absolute or the average absolute error can be calculated as
∴ΔTavg=5ΔT1+ΔT2+ΔT3+ΔT4+ΔT5
Putting the above values, we get
ΔTavg=50.01+0.06+0.20+0.09+0.18
ΔTavg=0.108s
Rounding off to two decimal places, we get
ΔTavg=0.11s
So we get the average absolute error to be equal to 0.11s
Hence, the correct answer is option B.
Note:
While calculating the absolute errors, we should not forget to take the modulus of the differences. As the name suggests, the absolute error is the magnitude of the deflection of a measurement from its mean value. If the modulus is not taken, then we may get the mean of the absolute errors as incorrect.