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Question

Question: The period of \({\cot h}\left( \frac{nx}{4} \right)\) is....

The period of coth(nx4){\cot h}\left( \frac{nx}{4} \right) is.

A

πin\frac{\pi i}{n}

B

4πin\frac{4\pi i}{n}

C

nπi4\frac{n\pi i}{4}

D

πi\pi i

Answer

4πin\frac{4\pi i}{n}

Explanation

Solution

coth(nx4)=coth(πi+nx4)=cothn4(4πin+x)\coth\left( \frac{nx}{4} \right) = \coth\left( \pi i + \frac{nx}{4} \right) = {\cot h}\frac{n}{4}\left( \frac{4\pi i}{n} + x \right)

∴ Period is 4πin\frac{4\pi i}{n}.