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Question

Question: The period of a simple pendulum is doubled, when...

The period of a simple pendulum is doubled, when

A

Its length is doubled

B

The mass of the bob is doubled

C

Its length is made four times

D

The mass of the bob and the length of the pendulum are doubled

Answer

Its length is made four times

Explanation

Solution

T=2πlgT = 2\pi\sqrt{\frac{l}{g}}TlT \propto \sqrt{l}