Question

The period of a particle executing SHM is 8 sec. At t = 0 it is at the mean position. The ratio of the distances covered by the particle in the 1^st second to the 2^nd second is :

• A. $\frac { 1 } { \sqrt { 2 } + 1 }$
• B. $\sqrt { 2 }$
• C. $\frac { 1 } { \sqrt { 2 } }$
• D. $\sqrt { 2 } + 1$

Answer 1

Answer: (D)

$\sqrt { 2 } + 1$

Answer 2

x = Asin

x₁ = Asin$\frac { \pi } { 4 }$ = $\frac { \pi } { 2 }$ = A

$\sqrt { 2 }$ + 1