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Question: The period of a body under SHM i.e. presented by \(T = P^{a}D^{b}S^{c}\); where \(P\) is pressure, \...

The period of a body under SHM i.e. presented by T=PaDbScT = P^{a}D^{b}S^{c}; where PP is pressure, DD is density and SS is surface tension. The value of a,ba,b and cc are

A

32,12,1- \frac{3}{2},\frac{1}{2},1

B

1,2,3- 1, - 2,3

C

12,32,12\frac{1}{2}, - \frac{3}{2}, - \frac{1}{2}

D

1,2,131,2,\frac{1}{3}

Answer

32,12,1- \frac{3}{2},\frac{1}{2},1

Explanation

Solution

By substituting the dimension of each quantity we get T=[ML1T2]a[L3M]b[MT2]cT = \lbrack ML^{- 1}T^{- 2}\rbrack^{a}\lbrack L^{- 3}M\rbrack^{b}\lbrack MT^{- 2}\rbrack^{c}

By solving we get a = – 3/2, b = 1/2 and c = 1