Question
Question: The period of a body under SHM i.e. presented by \(T = P^{a}D^{b}S^{c}\); where \(P\) is pressure, \...
The period of a body under SHM i.e. presented by T=PaDbSc; where P is pressure, D is density and S is surface tension. The value of a,b and c are
A
−23,21,1
B
−1,−2,3
C
21,−23,−21
D
1,2,31
Answer
−23,21,1
Explanation
Solution
By substituting the dimension of each quantity we get T=[ML−1T−2]a[L−3M]b[MT−2]c
By solving we get a = – 3/2, b = 1/2 and c = 1