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Question: The perimeter of a quadrant of a circle of radius r is: (a) \(\dfrac{\pi r}{2}\) (b) \(2\pi r\...

The perimeter of a quadrant of a circle of radius r is:
(a) πr2\dfrac{\pi r}{2}
(b) 2πr2\pi r
(c) r2(π+4)\dfrac{r}{2}\left( \pi +4 \right)
(d) 2πr+r22\pi r+\dfrac{r}{2}

Explanation

Solution

Here, we will try to find the perimeter of the quadrant of a circle by using the formula for the perimeter of a circle which is 2πr2\pi r. We will the concept that a quadrant of a circle is one-fourth of a circle.

Complete step-by-step answer:

We know that a circle is defined as the locus of all the points that are equidistant from a fixed point called the centre of the circle. Now, a quadrant is one-fourth section of a circle which is obtained when a circle is divided evenly into four sections or rather 4 quadrants by a set of two lines which are perpendicular in nature.
Since, quadrant refers to the four quarters in the coordinate system. But, when it comes to a circle, the quarter of a circle is called a quadrant, which is a section of 90 degrees. When four such quadrants are joined, then we get a complete circle.
If the radius of a circle is r, then the perimeter of the circle is given as:
P=2πrP=2\pi r
While finding the perimeter of a quadrant we need to add two times the radius of the circle to the perimeter of the curved boundary.
Perimeter of the curved boundary= 14×2πr\dfrac{1}{4}\times 2\pi r= πr2\dfrac{\pi r}{2}
Now, on adding two times the radius of the circle to πr2\dfrac{\pi r}{2}, we get:
2r+πr2 =r2(π+4) \begin{aligned} & 2r+\dfrac{\pi r}{2} \\\ & =\dfrac{r}{2}\left( \pi +4 \right) \\\ \end{aligned}
Hence, option (c) is the correct answer.
Note: Students should note here that the quadrant of a circle is one-fourth section of the circle. So, for finding the perimeter of the quadrant, we have to take one-fourth of the circumference of the circle. One should also keep in mind that two times the radius of the circle have to be added to on-fourth the circumference of the circle.