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Question

Mathematics Question on Trigonometric Functions

The perimeter of a certain sector of a circle is equal to the length of the arc of the semicircle. Then the angle at the centre of the sector in radians is

A

π2\pi -2

B

π+2\pi +2

C

π3\frac {\pi} {3}

D

2π3\frac {2\pi} {3}

Answer

π2\pi -2

Explanation

Solution

Let the radius of circle be rr.
\therefore\,\,\, Length of an arc =θ360×2πr=\frac{\theta}{360^{\circ}} \times 2\,\pi r
Since, perimeter of a sector of a circle = = length of the arc of the semicircle.
θ360×2πr+2r=πr\therefore\,\,\,\, \frac{\theta}{360^{\circ}} \times 2 \pi r+2 r=\pi r
θ+2=π\Rightarrow\,\,\,\,\, \theta+2=\pi
θ=π2\Rightarrow\,\,\,\,\, \theta=\pi-2