Question
Question: The percentage of \[Se\] in peroxidase anhydrous enzyme is \(0.5\% \) by weight \((At.\;wt. = 78.4)\...
The percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (At.wt.=78.4) then, what would be the minimum molecular weight of peroxidase anhydrous enzyme?
A) 1.568×104
B) 1.568×103
C) 15.68
D) 2.136×104
Solution
As we know that mass percentage is basically the ratio where given mass of the substance is present in 100g of total mass of the compound and we also know that the moles is the ratio of the given mass of the substance or solute to the molecular mass of the solvent.
Formula used: Mass%=molecularmassofcompoundgivenmassofatom×100
Complete answer:
We know that mass percent of an element is the percentage or composition of a component in a compound where the percent of the total mass of the compound is due to that component only.
In the question, we are given that Selenium is present in a peroxidase anhydrous enzyme as 0.5g in 100g of enzyme and the atomic mass of selenium is 78.4g.
So let us consider the molecular mass of the given peroxidase anhydrous enzyme be xgmol−1.
We know that one mole of peroxidase anhydrous enzyme will contain a minimum of one mole of selenium or we can say that one molecule of peroxidase anhydrous enzyme will contain a minimum of one atom of selenium.
So, we can say that 78.4g of selenium will be present in xgmol−1of peroxidase anhydrous enzymes. So the mass percentage can be given as:
⇒Mass%=molecularmassofcompoundgivenmassofatom×100
⇒Mass%ofSe=x78.4×100
⇒Mass%ofSe=x7840
Now we can calculate the percentage of selenium which is present as 0.5% by weight in peroxidase anhydrous enzymes. We will get:
⇒0.5=x7840
⇒x=0.57840=1.568×104gmol−1
Therefore from the above solution we can say that the correct answer is (A).
Note: Remember that percentage composition of the compound is the relative mass of the each of the constituent element in 100 parts of it or mass percent of an element is the ratio of mass of that element in one mole of the compound to the molar mass of the compound multiplied by 100. We can also check the purity of a given sample by analysing the percentage composition.