Question

The percentage composition of carbon by mole in methane is :

• A. 0.8
• B. 0.25
• C. 0.75
• D. 0.2

Answer 1

Answer: (D)

0.2

Answer 2

In $CH_4$
Mole of carbon $n_C = 1$
Mole of hydrogen $= n_H = 4$
$\%$ of $n_{C} = \frac{n_{C}}{_{n_C} +_{n_H}}\times100 = \frac{1}{5} \times 100 = 20\%$