Question

The peak value of an Alternating current is 6 amp, then r.m.s. value of current will be

• A. 3 A
• B. $3\sqrt{3}$A
• C. $3\sqrt{2}$A
• D. $2\sqrt{3}$A

Answer 1

Answer: (C)

$3\sqrt{2}$A

Answer 2

$i_{r.m.s} = \frac{6}{\sqrt{2}} = 3\sqrt{2}\mspace{6mu} A$