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Question

Physics Question on AC Voltage

The peak value of alternating current is 525\sqrt{2} ampere. The mean square value of current will be:

A

5A5\,\,A

B

2.5A2.5\,\,A

C

525\sqrt{2}

D

none of these

Answer

5A5\,\,A

Explanation

Solution

Given, I0=52I_0 = 5 \sqrt 2 A Root mean-square value of current Irms=I02=522=5AI_{ rms} = \frac{ I_0}{ \sqrt 2} = \frac{ 5 \sqrt 2}{ \sqrt 2} = 5 \,A