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Question: The particles start simultaneously from the same point and move along two straight lines, one with u...

The particles start simultaneously from the same point and move along two straight lines, one with uniform velocity u\overset{\rightarrow}{u} and the other from rest with uniform acceleration f\overset{\rightarrow}{f}. Let α\alpha be the angle between their directions of motion. The relative velocity of the second particle w.r.t. the first is least after a time

A

usinαf\frac{u\sin\alpha}{f}

B

fcosαu\frac{f\cos\alpha}{u}

C

usinαu\sin\alpha

D

ucosαf\frac{u\cos\alpha}{f}

Answer

ucosαf\frac{u\cos\alpha}{f}

Explanation

Solution

After t, velocity = f×tf \times t

VBA=ft+(u)V_{BA} = \overset{\rightarrow}{f}t + ( - \overset{\rightarrow}{u})

VBA=f2t2+u22futcosαV_{BA} = \sqrt{f^{2}t^{2} + u^{2} - 2fut\cos\alpha}

For max. and min., ddt(VBA2)=2f2t2fucosα=0\frac{d}{dt}(V_{BA}^{2}) = 2f^{2}t - 2fu\cos\alpha = 0

t=ucosαft = \frac{u\cos\alpha}{f}