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Question

Physics Question on work

The particle of mass 50kg50\, kg is at rest. The work done to accelerates it by 20m/s20\,m/s in 10s10\,s is

A

103J10^3 J

B

104J10^4 J

C

2×103J2 \times 10^3 J

D

4×104J4 \times 10^4 J

Answer

104J10^4 J

Explanation

Solution

v=u+atv=u+a t 20=0+a×1020 =0+a \times 10 20=a×1020 =a \times 10 a=2m/s2a =2 \,m / s ^{2} Then, s=ut+12at2s=u t+\frac{1}{2} a t^{2} s=0+12×2×10×10s=0+\frac{1}{2} \times 2 \times 10 \times 10 s=100ms=100 \,m Work done W=F×sW=F \times s or or W=ma×sW= ma \times s W=50×2×100\therefore W =50 \times 2 \times 100 W=10000=104JW =10000=10^{4} J