Question

The particle executing simple harmonic motion has a kinetic energy $K_0 \cos^2 \omega t$.. The maximum values of the potential energy and the total energy are respectively

• A. $K_0 / 2$ and $K_0$
• B. $K_0$ and $2K_0$
• C. $K_0$ and $K_0$
• D. 0 and $2 K_0$

Answer 1

Answer: (C)

$K_0$ and $K_0$

Answer 2

$\because K.E. = K _{0} \cos ^{2} \omega t$
$\therefore$ Maximum $P.E. =$ Maximum $K.E$
$=$ Total energy $= K _{0}$