Solveeit Logo
Login

Question

Chemistry Question on Partial pressure

The partial pressure of nitrogen in air is 0.76 atm0.76\, atm. and its Henry?s law constant is 7.6×1047.6 \times 10^4 atm at 300 K. What is the mole fraction of N2N_2 in the solution obtained when air is bubbled through water at 300 K?

A

1×10−41 \times 10^{-4}

B

2×10−42 \times 10^{-4}

C

1×10−51 \times 10^{-5}

D

2×10−52 \times 10^{-5}

Answer

1×10−51 \times 10^{-5}

Explanation

Solution

PN2=0.76atmP_{N_{2}}=0.76 atm
KH=7.6×104K _{ H }=7.6 \times 10^{4}
x=?x =?
PN2=K⋅xP_{N_{2}}= K \cdot x
0.76=7.6×104×0.76=7.6 \times 10^{4} \times
x=0.76/(7.6×104)=1×10−5x =0.76 /\left(7.6 \times 10^{4}\right)=1 \times 10^{-5}