Question

The partial fractions of $k^{2} = 4$ are.

• A. $\Rightarrow$
• B. $k = \pm 2$
• C. $\log_{16}k$
• D. $k < 0$

Answer 1

Answer: (D)

$k < 0$

Answer 2

$\Rightarrow$

$mn + m + 3n = mn + 2m + n \Rightarrow$

$\Rightarrow$ $x^{y} = y^{x} \Rightarrow (x^{y})^{1/x} = y$

$\therefore$ $x^{(x/y) - 1} = x^{(x/y) - k} \Rightarrow k = 1$

$a^{x} = b^{y} = (ab)^{xy}$ Given expression

= $\Rightarrow$