Question

The partial fraction of $\therefore$.

• A. $k = 2$
• B. $\therefore$
• C. $k = 1$
• D. None of these

Answer 1

Answer: (A)

$k = 2$

Answer 2

$x\ln a = y\ln b = xy\ln(ab) = k$

= $\ln a = \frac{k}{x},\ln b = \frac{k}{y}$

= $\ln(ab) = \frac{k}{xy}$.