Question

The parametric equation of a parabola is x = 4t2, y = 8t. The tangents at the points whose parameters are $\frac{1}{2}$ and 1 meet on the line –

• A. x = 2
• B. x = 6
• C. y = 2
• D. x + y = 6

Answer 1

Answer: (A)

x = 2

Answer 2

Compared to the standard form a = 4.

Point of intersection of tangent is (at1t2, a(t1 + t2))

i.e., (2, 6) and this lies on x = 2.