Solveeit Logo
Login

Question

Chemistry Question on Chemical bonding and molecular structure

The paramagnetic property of the oxygen molecule is due to the presence of unpaired electrons present in

A

(s2px)1 and (s2px)1(s2p_x)^1\, and\, (s2p_x)^1

B

(s2px)1 and (π2py)1(s2p_x)^1\, and\, (\pi2p_y)^1

C

(pi∗2px)1 and (π∗2px)1(pi^*2p_x)^1\, and\, (\pi^*2p_x)^1

D

(pi∗2py)1 and (π2py)1(pi^*2p_y)^1\, and\, (\pi2p_y)^1

Answer

(pi∗2px)1 and (π∗2px)1(pi^*2p_x)^1\, and\, (\pi^*2p_x)^1

Explanation

Solution

The electronic configuration of oxygen molecule is as :
O2:KKs2s2,s∗2s2,s∗2sz2,π2px2≈π2py2,π∗2px1,π∗2py1O_2 :KKs 2s^2, s^*2s^2,s^*2s^2_z, \pi 2p^2_x \approx\pi 2p^2_y,\pi^*2p^1_x, \pi^*2p^1_y
The molecule has paramagnetic character due to the presence of two unpaired electrons (π∗2px)1 and (π∗2py)1(\pi^*2p_x)^1\, and\, (\pi^*2p_y)^1.