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Question: The parallelism condition for two straight lines one of which is specified by the equation \(a x + b...

The parallelism condition for two straight lines one of which is specified by the equation ax+by+c=0a x + b y + c = 0the other being represented parametrically by x=αt+βx = \alpha t + \beta y=γt+δy = \gamma t + \delta is given by.

A

, β=δ=c=0\beta = \delta = c = 0

B

aαbγ=0a \alpha - b \gamma = 0 , β=δ=0\beta = \delta = 0

C

aα+bγ=0a \alpha + b \gamma = 0

D

aγ=bα=0a \gamma = b \alpha = 0

Answer

aα+bγ=0a \alpha + b \gamma = 0

Explanation

Solution

Given lines are ax+by+c=0a x + b y + c = 0 .....(i)

and x=αt+β,y=γt+δx = \alpha t + \beta , y = \gamma t + \delta

After eliminating t, we get γxαy+αδγβ=0\gamma x - \alpha y + \alpha \delta - \gamma \beta = 0 .....(ii)

For parallelism condition, aγ=bα\frac { a } { \gamma } = \frac { b } { - \alpha }aα+bγ=0a \alpha + b \gamma = 0 .