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Question

Mathematics Question on applications of integrals

The parabola having its focus at (3,2)(3, 2) and directrix along the yy-axis has its vertex at

A

(2, 2)

B

(32,2)\left(\frac{3}{2} , 2 \right)

C

(12,2)\left(\frac{1}{2} , 2 \right)

D

(23,2)\left(\frac{2}{3} , 2 \right)

Answer

(32,2)\left(\frac{3}{2} , 2 \right)

Explanation

Solution

Vertex of the parabola is a point which lies on the axis of the parabola, which is a line \bot to the directrix through the focus, i.e., y=2y = 2 and equidistant from the focus and directrix x=0x = 0, so that the vertex is (32,2)\left(\frac{3}{2} , 2\right) .