Question

The pair that has similar shape is
A. $B{F_3},Br{F_3}$
B. ${S_2}{F_2},{S_2}C{l_2}$
C. ${O_2}{F_2},{S_2}C{l_2}$
D. ${B_2}{H_6},{N_2}{H_4}$

Answer 1

${S_2}{F_2}$ and ${S_2}C{l_2}$ both have $s{p^3}d$ hybridization and has the shape which is similar to ${H_2}{O_2}$. In the same way, ${O_2}{F_2}$ has the structure similar to ${H_2}{O_2}$.

Complete step by step answer:
$B{F_3}$ have the $s{p^2}$ hybridization but $Br{F_3}$ (Bromine Trifluoride) have the $s{p^3}d$ hybridization. So, $B{F_3}$ is triangular (Trigonal planar) in shape having bond angle $120^\circ$ but $Br{F_3}$ is ‘T’ shaped or trigonal bipyramidal with a bond angle of $86.2^\circ$.

${S_2}{F_2}$ (Disulphuric difluoride) is a halide of sulphur have the $s{p^3}{d^{}}$ hybridization. Its shape is gauche (half-open book shape) which is similar to ${H_2}{O_2}$ with bond angle of $108.3^\circ .{S_2}C{l_2}$ is a polar molecule and has $s{p^3}d$ hybridization. It has the shape of gauche.

${O_2}{F_2}$ has the structure similar to ${H_2}{O_2}$. It has the shape of a half-open book (gauche in shape) ${S_2}C{l_2}$ also has the shape similar to ${O_2}{F_2}$.

In (Diborane), Boron is $s{p^3}$ hybridised, there are two terminals $B - H$ bonds for each boron atom and there are only 12 bonding electrons available. The structure of Diborane molecule consists of 4 H atoms and that of two boron atoms coming on the same plane. In between these planes, there are said to be two dividing atoms of H. The two atoms of B left with that of each unpaired electron orbital and empty orbital forms the two bridging’s $\left( {B-H-B} \right)$ bonds with that of the two 1s hydrogen atoms, is also called as the banana bond and on the other hand, ${N_2}{H_4}$ (Nitrogen hydride or Hydrazine) is a strong base. Each subunit of ${H_2}N - N$ is pyramidal and $N - N$ bond distance is about $1.4A^\circ$.

Therefore, the correct answer is option (B) and (C).

Note: Diborane is a chemical compound that consists of boron (B) and hydrogen (H) atoms and has a molecular formula ${B_2}{H_6}$. This substance is highly unstable at the room temperature and has a sweet odour. The compounds consisting of boron and hydrogen atoms are called boranes and diborane is one of the simplest boron hydrides.