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Chemistry Question on coordination compounds

The pair(s) of complexes wherein both exhibit tetrahedral geometry is(are)
(Note: py = pyridine, Given: Atomic numbers of Fe, Co, Ni and Cu are 26, 27, 28 and 29, respectively)

A

[FeCl4]−and[Fe(CO)4]2−[FeCl_4]^{-} \quad \text{and} \quad [Fe(CO)_4]^{2-}

B

[Co(CO)4]−and[CoCl4]2−[Co(CO)_4]^{-} \quad \text{and} \quad [CoCl_4]^{2-}

C

[Ni(CO)4]and[Ni(CN)4]2−[Ni(CO)_4] \quad \text{and} \quad [Ni(CN)_4]^{2-}

D

[Cu(py)4]+and[Cu(CN)4]3−[Cu(py)_4]^{+} \quad \text{and} \quad [Cu(CN)_4]^{3-}

Answer

[FeCl4]−and[Fe(CO)4]2−[FeCl_4]^{-} \quad \text{and} \quad [Fe(CO)_4]^{2-}

Explanation

Solution

[FeCl4]– → Fe3+, 3d5 (weak field ligand) = sp3
[Fe(CO)4]–2 → Fe2–, 3d10 →sp3
[Co(CO)4]– → Co–, 3d10 → sp3
[CoCl4]2– → Co2+, 3d7 (weak field ligand) → sp3
[Ni(CO)4] → Ni, 3d10 → sp3
[Ni(CN)4]2– → Ni2+, 3d8 (strong field ligand) → dsp2
[Cu(py)4]+ → Cu+, 3d10 →sp3
[Cu(CN)4]3– → Cu+, 3d10 → sp3
In 3d10 electronic configuration, only sp3 hybridisation and tetrahedral geometry are possible.