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Question

Physics Question on Surface tension

The pair of quantities having same dimensions is

A

Impulse and Surface Tension

B

Angular momentum and Work

C

Work and Torque

D

Young's modulus and Energy

Answer

Work and Torque

Explanation

Solution

Impulse = Force ×\times time
=[MLT2][T]=[MLT^{-2}][T]
=[MLT1]=[MLT^{-1}]

Surface tension=Forcelength=\frac{\text{Force}}{\text{length}}
=[MLT2][L]=\frac{[MLT^{-2}]}{[L]}
=[ML0T2]=[ML^0T^{-2}]
Angular momentum
= Moment of inertia ×\times angular velocity
=[ML2][T1]=[ML^2][T^{-1}]
=[ML2T1]=[ML^2T^{-1}]
Work = Force ×\times distance
=[MLT2][L]=[MLT^{-2}][L]
=[ML2T2]=[ML^2T^{-2}]
Energy =[ML2T2]=[ML^2T^{-2}]
Torque = Force ×\times distance
=[MLT2][L]=[MLT^{-2}][L]
=[ML2T2]=[ML^2T^{-2}]
Young's modulus
=Force / AreaChange in length / original length=\frac{\text{Force / Area}}{\text{Change in length / original length}}
=[MLT2]/[L2][L]/[L]=\frac{[MLT^{-2}]/[L^2]}{[L]/[L]}
=[ML1T2]=[ML^{-1}T^{-2}]
Hence, among the given pair of physical quantities work and torque have the same dimensions
[ML2T2][ML^2T^{-2}].