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Question

Mathematics Question on Solution of a Linear Equation

The pair of linear equations a1x+b1y+c1=0a_1x+b_1y+c_1=0 and a2x+b2y+c2=0a_2x+b_2y+c_2=0 has a unique solution, then

A

a1a2b1b2\frac {a_1}{a_2} ≠ \frac {b_1}{b_2}

B

a1a2=b1b2c1c2\frac {a_1}{a_2} = \frac {b_1}{b_2} ≠ \frac {c_1}{c_2}

C

a1a2=b1b2=c1c2\frac {a_1}{a_2} = \frac {b_1}{b_2} = \frac {c_1}{c_2}

D

a1a2=b1b2\frac {a_1}{a_2} = \frac {b_1}{b_2}

Answer

a1a2b1b2\frac {a_1}{a_2} ≠ \frac {b_1}{b_2}

Explanation

Solution

The correct option is (A): a1a2b1b2\frac {a_1}{a_2} ≠ \frac {b_1}{b_2}.