Question

The pair of compounds which cannot exist together in the solution is:
A. $NaHC{O_3}\,\,and\,\,NaOH$
B. $NaHC{O_3}\,\,and\,\,{H_2}O$
C. $NaHC{O_3}\,\,and\,\,N{a_2}C{O_3}$
D. $N{a_2}C{O_3}\,\,and\,\,NaOH$

Answer 1

To solve this question, we must first understand that in order to exist together in a solution, they must not react with each other. Then we need to for every provided set of compounds whether they will react with each other in a solution or not and then only we can conclude the correct answer.

Complete answer:
Before we move forward with the solution of this given question, let us first understand some basic concepts:
Step 1: As we know that, $NaHC{O_3}\,\,and\,\,NaOH$​ cannot exist together in the solution as they react with each other. $NaHC{O_3}$​ is acidic and is decomposed by $NaOH$forming $N{a_2}C{O_3}$ ​.
The reaction is as follows:
$NaHC{O_3}\,\, + \,\,NaOH\,\, \to \,\,N{a_2}C{O_3}\,\, + \,\,{H_2}O$
So, this is our required answer because the question is single correct and our very first option is correct and we must not move forward in order to check out all the options one by one.
But for Our knowledge:
Step 2: $NaHC{O_3}\,\,and\,\,{H_2}O$: They will not react with each other, because $NaHC{O_3}$ is an acid and it will get diluted after adding it to water.
Step 3: $NaHC{O_3}\,\,and\,\,N{a_2}C{O_3}$: They will also not react with each other because $N{a_2}C{O_3}$ is formed by the reaction of $NaHC{O_3}\,\,and\,\,NaOH$ itself.
Step 4: $N{a_2}C{O_3}\,\,and\,\,NaOH$: They will also not react with each other because $N{a_2}C{O_3}$ is formed by the reaction of $NaHC{O_3}\,\,and\,\,NaOH$ itself.

So, clearly we can conclude that the correct answer is, ‘A. $NaHC{O_3}\,\,and\,\,NaOH$’

Note: One substance will react with another if the reaction is “spontaneous”. Dr. Gibbs gave us a super cool equation that lets us predict if a reaction will happen. If the energy of a reaction is lower as a product than a reactant, the reaction will happen.