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Question: The oxide that gives \(H_{2}O_{2}\)on treatment with dilute \(H_{2}SO_{4}\)is...

The oxide that gives H2O2H_{2}O_{2}on treatment with dilute H2SO4H_{2}SO_{4}is

A

PbO2PbO_{2}

B

BaO2,8H2OBaO_{2},8H_{2}O

C

MnO2MnO_{2}

D

TiO2TiO_{2}

Answer

BaO2,8H2OBaO_{2},8H_{2}O

Explanation

Solution

:

}{+ 8H_{2}O_{(l)}}$$