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Question

Chemistry Question on Oxidation Number

The oxidation states of CrCr in [Cr(H2O)6]Cl3,[Cr(C6H6)2] [Cr(H_2O)_6]Cl_3, [Cr(C_6H_6)_2], and K2[Cr(CN)2(O)2(O2)(NH3)]K_2[Cr(CN)_2(O)_2(O_2)(NH_3)] respectively are :

A

+3, +4, and +6

B

+3, +2, and +4

C

+3, 0, and +6

D

+3, 0, and +4

Answer

+3, 0, and +6

Explanation

Solution

[Cr(H2O)6]Cl3\left[ Cr \left( H _{2} O \right)_{6}\right] Cl _{3}
x+0×61×3=0\Rightarrow x +0 \times 6-1 \times 3=0
x=+3\therefore x =+3
[Cr(C6H6)2]\left[ Cr \left( C _{6} H _{6}\right)_{2}\right]
x+2×0=0\Rightarrow x +2 \times 0=0
x=0x =0
K2[Cr(CN)2(O2)(O2)NH3]K _{2}[ Cr \left.( CN )_{2}\left( O _{2}\right)\left( O _{2}\right) NH _{3}\right]
1×2+x1×22×22×1=0\Rightarrow 1 \times 2+ x -1 \times 2-2 \times 2-2 \times 1=0
x6=0\Rightarrow x -6=0
x=+6x =+6