Question

The oxidation state of V in$Rb_{4}Na\left\lbrack HV_{10}O_{28} \right\rbrack$ is

• A.
  • 2
• B.
  • 5
• C. – 2
• D. – 5

Answer 1

Answer: (B)

• 5

Answer 2

The oxidation state of Rb = +1 (Since it is alkali metals)

Let oxidation state of V = x

$\therefore$ $4 \times 1 + 1 + 1 + 10x + 28 \times ( - 2) = 0$

or $6 + 10x - 56 = 0$ or $10x - 50 = 0$ or $x = 5$

$\therefore$ The oxidation state of V = +5