Question

The oxidation state of the most electronegative element in the products of the reaction. $BaO_2$ with dil, $H_2SO_4$ are

• A. 0 and - 1
• B. - 1 and - 2
• C. - 2 and 0
• D. - 2 and - 1

Answer 1

Answer: (D)

- 2 and - 1

Answer 2

The correct option is(D): - 2 and - 1.

The reaction involved is $BaO_2 + H_2SO_4 \rightarrow BaSO_4 + H_2O_2$ The most electronegative atom, oxygen, in $BaSO_4$ and
$H_2O_2$ has - 2 and - 1 oxidation state respectively.