Question

The oxidation state of oxygen in $O_2 Pt F_6$

• A. 0
• B. 1
• C. $+ \frac{1}{2}$
• D. $- \frac{1}{2}$

Answer 1

Answer: (C)

$+ \frac{1}{2}$

Answer 2

In $O_2$ Pt $F_6$, the O.N. of Pt = + 5 Therefore,$2 x + 5 - 6 = 0$ or $2 x = 1$ or $x = + \frac{1}{2}$