Question

The oxidation state of osmium (Os) in ${OsO_4}$ is

• A. 7
• B. 6
• C. 4
• D. 8

Answer 1

Answer: (D)

8

Answer 2

${OsO_4}$ Let O.N. of Os be x then 1 $\times$ (x) + 4(-2) = 0 $\therefore$ x = 8